In a series RLC circuit, power is dissipated only by the resistor. The power delivered is given by P = I²R. Given I = 2.5 A (assuming RMS current) and R = 40 Ω, P = (2.5)² × 40 = 6.25 × 40 = 250 W. (The provided option of 25W seems to be a typo for 250W).