Alright, let’s tackle this one together. So, for a photon, momentum \(p\) is given by \(p = \frac{h}{\lambda}\). Here your wavelength is \(0.01\) Å, which is \(1\times10^{-12}\) meters, so plugging that in you’ll get \(p = \frac{h}{1\times10^{-12}}\) — that’s \(10^{12}h\), which matches option C.  

Do you want me to walk through why we use \(p = h/\lambda\) for photons, so it sticks better?